https://www.55188.com/space-uid-1030967.html
N 0 50 15 N1 0 300 5 N2 0 300 10 N3 0 300 30 MS=(MAX(MAX(MA(C,n1),MA(C,n2)),MA(C,n3))-MIN(MIN(MA(C,n1),MA(C,n2)),MA(C,n3)))/((MA(C,n1)+MA(C,n2)+MA(C,n3))/3)*1000; a1:=COUNT(MS
作者:酣畅淋漓 |发布:2009-07-09 11:11:21